Question

The electrostatics force of repulsion between two positively charged ions carrying equal charge is 3.7  10−9 N, when they are separated by a distance of 5A°. Charge on ions will be

Answer 1

Explanation:

$f = \frac{1}{4\pi \: eo} \times \frac{q1q2}{ {r}^{2} }$

as both are proton so u can write q2

now by putting the values u can easily get

q