Chemistry, asked by sreerajkvkichukv, 8 months ago

The element Cu with atomic number 29 undergoes chemical reaction to form an ion with oxidation number +2..
a)write the subshell electronic configuration of this element.
b)can element show variable valency? why?
c)write down the chemical formula of one compound formed when this element reacts with chorine(11 Cl)​

Answers

Answered by manasgames237
20

Answer:

The answer to the following questions are:

(a) The element with atomic number 29 is Copper (Cu).

- Its ground state electronic configuration is:

Cu (29) = 1s², 2s², 2p⁶,3s², 3p⁶, 4s¹, 3d¹⁰

- In +2 oxidation state, the ion is Cu²⁺.

- Its electronic configuration is:

Cu²⁺ = 1s², 2s², 2p⁶, 3s², 3p⁶, 3d⁹

(b) Yes, this element, i.e., Copper can show variable valency.

- Copper is a transition element and hence it exhibits variable valency.

- Cu can show two valencies namely +1 and +2.

- Cu can only show two valencies because it has too much d electrons and hence fewer orbitals for the sharing of electrons.

Explanation:

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Answered by qwmagpies
0

Cu has atomic number 29.

  • a)Cu is a transition element of 3d group.
  • It has an electronic configuration as follows-
  •  {1s}^{2}  {2s}^{2}  {2p}^{6}  {3s}^{2}  {3p}^{6}  {4s}^{2}  {3d}^{9}
  • b) Yes, this element can show variable valency. It can remove its two electrons from the 4s orbital and can show +2 valency. Again it can transfer its electron to 3d orbital to compete for the octet and show +1 valency.
  • c) When Cu+2 reacts with chlorine copper chloride is formed.
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