Chemistry, asked by sonalsagar13, 1 year ago

The element having least difference in the values of first and second ionization potential is
a. Na
b. K
c. Li
d. Mg
(Give reason also)

Answers

Answered by ooday004
50

Answer:Mg

Explanation:in case of Mg after removing 2 electrons only inert gas configuration is attained but sodium and potassium gets it after removing only one electron

So in case of Na and k second I. E isomer so high and first I. E isomer very less but the difference in the 2 values is very high, lithium after removing one electron gets helium configuration, so the difference is less in case of Magnesium

Answered by mindfulmaisel
24

The element having least difference in the values of first and second ionization potential is magnesium (Mg).

Option: (d)

Explanation:  

  • Sodium, Potassium, and Lithium are alkali metal. So this metal are just one electron more than the inert gas configuration.  
  • The inert gas configuration is very stable so a large amount of ionization energy is required to remove the second electron from these elements.  
  • But in the case of magnesium it has two electrons more than the inert gas configuration.
  • Hence very less amount of energy is required to remove the electron from the unipositive ion.  
  • So the difference between the first and the second ionization potential is very less in case of magnesium.

Learn more about magnesium

Which mass of magnesium sulphate will be formed if 12 g of magnesium are reacted with sulphuric acid?

https://brainly.in/question/8876515

Why magnesium ribbon is choosen and not magnesium rod in the above experiment?

https://brainly.in/question/1580724

Similar questions