Question

The element with quantum numbers n = 2, l = 1, m = 1, s = -1/2 has the following position in the periodic table??
Explain in detailed please

Answer 1

Explanation:

Here outer most electron enters into the 3d hence the element belongs to d−block, number of group for d−block element= no. of electrons in (n-1)orbital + no. of electrons in n orbital=2+1=3 hence, the element belongs to 3rd group. Here principal quantum number is equal to the period of the element hence the element belongs to 4th period.