Question

The emf induced in a conductor of machine driven at 600 rpm, the
peak value of flux density is 1.0 Wb/m², diameter of machine 2.0
meter and length of machine 0.30 m is:
(a) 41.83 V
(6) 29.58 V
(c) 9.42 V
(d) 18.84 V​

Answer 1

bleπnd/60

1×0.30×π×2×600/60

18.84v

Answer 2

The EMF induced in a conductor is 18.84V. Therefore, option 'D' is correct.

Given:-

No. of turns per minute (n) = 600rpm

Flux density (b) = 1.0Wb/m²

Diameter (d) = 2.0m

Length (l) = 0.3m

To Find:-

The EMF induced in a conductor.

Solution:-

To find the EMF of the conductor, you need to follow these simple steps, as given below.

Now,

No. of turns per minute (n) = 600rpm

Flux density (b) = 1.0Wb/m²

Diameter (d) = 2.0m

Length (l) = 0.3m

EMF (E) = ?

(Here, all the physical quantities are in their respective SI units so, there is no need to change them)

According to the formula,

E =

$\frac{change \: in \: flux}{per \: unit \: time}$

Flux =

$b \times a \times \cos(0) \times n$

E =

$\frac{ n\times \: b \times l\times d \times \: \pi }{t}$

E =

$\frac{600 \times 1 \times 0.3 \times 2 \times \pi}{60}$

E =

$10 \times 0.6 \times 3.14$

E = 18.84V

Hence, the EMF induced in a conductor is 18.84V. Therefore, option 'D' is correct.

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