Question

The emf of a cell containing sodium/copper electrodes is 3.05 V, if the electrode potential of copper
electrode is +0.34 V, the electrode reduction potential
of sodium is :

(1) -2.71 V
(2) +2.71 V
(3) -3.71 V
(4) +3.71 V​

Answer 1

Explanation:

The emf of a cell containing sodium/ copper electrodes is 3.05 V, if the electrode potential copper electrode is +0.34 V, the electrode potential of sodium is: 1) -2.71 V.

Answer 2

Answer:

1) -2. 71V

Explanation:

$E°cell =E°cathod -E°anode$

$3.05 = 0.34 - ( - 2.71)$

$= 3.05$

$\therefore$$Electrode\:potential\:of\:sodium\:is\:-2. 71V$