Question

the emf of battery a is balanced by a length of 80cm on a potentio meter wire.the emf of a standard cell 1v is balanced by 50cm.the emf of A is?(ans=1.6v)(current electricity)

Answer 1

E1/E2=l1/l2
E1/1=80/50
E1=1.6

Answer 2

Answer:

The  emf of A is = 1.6V

Explanation:

given that,

the emf of the battery is balanced by a length of = 80cm

the emf of the standard cell is = 1v and is balanced by 50cm

we know that,

potential difference is directly proportional to length.

E ∝ L

SO, E1 / E2 = L1 / L2

E1 / 1 = 80 / 50

E1 = 1.6 V

therefore, the emf of the battery A  is  E1 = 1.6V

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