Question

the empirical formula of an organic compound is ch2 o its vapour density is 45 the molecular formula of the compound is

Answer 1

molar mass= vapour density × 2 = 45×2 = 90
mass of CH2O = 12+2+16 = 30

90/30 = 3
so actual formula = (CH2O)3 = C3H6O3

Answer 2

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molar mass= vapour density × 2 = 45×2 = 90

mass of CH2O = 12+2+16 = 30

90/30 = 3

so actual formula = (CH2O)3 = C3H6O3

HOPE SO IT WILL HELP......