)The empirical formula of Boron Hydride is BH3. Calculate molecular formula when the measured mass of the compound is 27.66.
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Hi,
Here is your answer
Given:
Emperical Formula of Boron Hydride=BH₃
Measured mass(molar mass of emperical formula)=27.66
To Find:
Molecular formula
Solution:
Molecular mass of BH₃=10.81+3=13.81(molar mass of molecular formula)
Molecular formula is given by the equation
Molecular formula=n×empirical formula-equation 1
n=molar mass of molecular formula/molar mass of emperical formula
n=27.66/13.81
n=2
Substitute the value of n in equation 1
We get,
Molecular formula=2(BH₃)
Molecular formula=B₂H₆
Notes:
1.Molecular formula=n×empirical formula
2.n=molar mass of molecular formula/molar mass of emperical formula
Hope this helps you.
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