Chemistry, asked by AjayT7827, 8 months ago

)The empirical formula of Boron Hydride is BH3. Calculate molecular formula when the measured mass of the compound is 27.66.

Answers

Answered by TheValkyrie
15

Hi,

Here is your answer

Given:

Emperical Formula of Boron Hydride=BH₃

Measured mass(molar mass of emperical formula)=27.66

To Find:

Molecular formula

Solution:

Molecular mass of BH₃=10.81+3=13.81(molar mass of molecular formula)

Molecular formula is given by the equation

Molecular formula=n×empirical formula-equation 1

n=molar mass of molecular formula/molar mass of emperical formula

n=27.66/13.81

n=2

Substitute the value of n in equation 1

We get,

Molecular formula=2(BH₃)

Molecular formula=B₂H₆

Notes:

1.Molecular formula=n×empirical formula

2.n=molar mass of molecular formula/molar mass of emperical formula

Hope this helps you.

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