Question

The empirical formula of the compound is AlCl2. What is its molecular formula if its molecular weight is 213g? (Al = 27, Cl = 35.5)

If someone can please explain to me what is going on in that question, that would be greatly appreciated :) .

Answer 1

ANSWER

To find moles of each element using the average atomic mass of an element  to convert grams of each to moles as :

Al : 9 g x (1 mole/27 g) = 0.33333 moles 

Cl: 35.5 g x (1 mole/35.453 g) = 0.9987 moles 

 dividing both numbers by the smaller one as : 

0.33333/0.33333 = 1 

0.9987/0.33333 = 3 

Therefore the formula is : AlCl3

And its empirical formula is also  AlCl3 (a simple ratio of all elements of molecular formula)

Hope it helps

Mark it as BRAINLIEST if you are satisfied with the answer