Question

The energy ∆E corresponding to intense yellow line of sodium of lamda 589 nm is

Answer 1

Answer:

The answer is 33.72 x 10^-20 J.

Explanation:

The formula of ΔE = hv  

Here h = plank's constant = 6.626 x 10^-34 Js

v = frequecny

First calculate the frequency by using the formula.

v = c /λ

c = speed of light = 3 x 10^8 m/s

λ= 589 nm ( 1nm = 10^-9)

λ= 589 x 10^-9 m

v = 3 x 10^8 m/s /589 x 10^-9 m

v = 0.00509 x 10^17

v= 5.09 x 10^-3 x 10^17

v = 5.09 x 10^14Hz

Now calculate.

ΔE = hv =  6.626 x 10^-34 x 5.09 x 10^14

ΔE = 33.72 x 10^-34+14

ΔE = 33.72 x 10^-20 J

Answer 2

Answer:

hope u got it so plse mark as brainlist and follow me alia joshi