Question

the energy emitted per second by black body at 27 degree Celsius is 10 j . if the temprature of the black body is increased to 327 degree Celsius, the energy emitted per second will be ​

Answer 1

$E_2 = E_1 = ( \dfrac{T_2}{T_1} ) {}^{4} \\ \\ \: \: = \: 10( \dfrac{327 + 273}{27 + 273} ) {}^{4} \\ \\ = 160J$

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