Question

The energy of activation for a first order reaction is 104 kJ mol⁻¹. The rate constant at 25°C is 3.7 x 10⁻⁵ s⁻¹, What is the rate constant at 30°C.

Answer 1

The energy of activation for the first-order reaction = 104kJ mol^-1

Rate constant = 3.7 * 10^-5 s^-1 at 25 degree C

Rate constant =? at 30 degrees C

K = A * exp(Ea/RT)

This will give you the value of A which is a pre-exponential factor, then use the formula again with t 30 and you will get the value of K.

Answer 2

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