The energy of an electron in the first Bohr orbit is (- 13.6 eV) , then find the energy of He + in the same Bohr orbit .
Answers
Answered by
1
HEY MATE
ACCORDING TO ENERGY RELATIONSHIP (BOHR)
E=-13.6Z²/N²
GIVEN E¹=-13.6
SO N²=-13.6/-13.6(H ATOM)
N²=1
N=1
WHILE
E2=-13.6Z²/N2
E2=-13.6×4
E2=-54.4eV
HOPE HELP U
ACCORDING TO ENERGY RELATIONSHIP (BOHR)
E=-13.6Z²/N²
GIVEN E¹=-13.6
SO N²=-13.6/-13.6(H ATOM)
N²=1
N=1
WHILE
E2=-13.6Z²/N2
E2=-13.6×4
E2=-54.4eV
HOPE HELP U
Answered by
0
Answer:
Explanation:
The answer is given on the image.
Attachments:
Similar questions