Physics, asked by muskan9707, 1 year ago

The energy of electron in first excited state of H-atom is – 3.4 eV its kinetic energy is
(a) – 3.4 eV
(b) + 3.4 eV
(c) – 6.8 eV
(d) 6.8 eV

Answers

Answered by meldiv123
1
(B) + 3.4eV is the correct answer for the above given question dude...
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