Question

the energy of H-atom in nth orbit is En then energy in nth orbit of singly ionised helium atom will be

Answer 1

Energy Is proportional to Z^2/n^2

So If for hydrogen it is En=1/n^2

For helium =4/n^2=4En

Answer 2

The energy in nth orbit of singly ionised helium atom will be $4\times E_n$  

Explanation:

Using Rydberg equation:

$E=\frac{R_H}{n^2} \times Z^2$  (1)

Where,

E = energy

$R_H$ = Rydberg's Constant

n = energy level

Z= atomic number = 1 (for hydrogen)

Putting the values, in above equation, we get

$E_n=\frac{R_H}{n^2} \times 1^2$

${R_H}=E_n\times n^2$

For nth orbit , energy can be calculated for $He^+$ by using equation with atomic number of Z= 2

$E=\frac{E_n\times n^2}{n^2} \times 2^2$  

$E=4\times E_n$  

Learn More about energy of hydrogen atom

https://brainly.in/question/4797120

https://brainly.com/question/12034958