Physics, asked by debobratdoley, 11 months ago

the energy of photon (in ev) of wavelength 500A will be​

Answers

Answered by sahildhande987
1

Explanation:

Energy of photon=hc/laembda

E=(6.6*10^-34)*(3*10^8)/500

E=2*10^-26/500

E=1/2*5*10^24

E=1/10*10^24

E=10*10^-24

E=1*10^-23

Thank you

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