Question

The energy of second Bohr orbit of the hydrogen
atom is -328 kJ mol-1. The energy of the third
orbit of Li2+ will be
(1) -626 kJ mol-1 (2) -984 kJ mol-1
(3) -1312 kJ mol-1 (4) -328 kJ mol-1​

Answer 1

Answer:

option3

Explanation:

E =-1312×zxz/nxn.

=-1312×9/9

=-1312

Answer 2

Answer:y

Explanation:

E=1312*Z^2/n^2

where Z=3(atomic no.) n=3(no.of orbit

E=1312*3^2/3^2

E=1312*9/9

E=1312