Question

The energy required to ionise 2 mole of gaseous he+ ion present in its ground state is :

54.4 eV

​108.8NaeV

54.4NaeV

108.8eV

Please give working also.
Thank you.

Answer 1

we know, energy required to remove an electron from ground state of hydrogen like atom of atomic number Z is given by
$\bf{I.E=13.6Z^2eV/atom}$

so, energy required to remove an electron from ground state of He+ ion,
$\bf{I.E=13.6(2)^2=54.4eV/atom}$

A/C to question,
we have to find energy required to ionise 2moles of gaseous He+ ion present in its ground state is = ionisation energy of He × number of electron in 2 mole
= 54.4 × 2N eV
= 108.8 N eV , where N is Avogadro's number.

Answer 2

Answer:

hope this will help you