Chemistry, asked by shantamDey9350, 1 year ago

The energy required to remove the electron from a singly ionized helium atom is 2.2 times the energy required to remove an electron from helium atom. The total energy required to ionize the helium atom completely is :

Answers

Answered by Anonymous
24
⭐⭐⭐ Hey mate!!!⭐⭐⭐

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⚡⚡ Energy required to remove an electron from singly ionised helium atom will be

En= (13.6)×2^2

En= 54.4eV

Now ,

⚡Given energy required to remove electron from singly ionized helium atom is 2.2 times of the energy required to remove electron from helium atom..

So,

E He = 54.4/2.2

E He = 24.72

⚡total energy required will be energy required to remove electron from helium atom + energy required to remove electron from singly ionised helium atom.

⚡⚡E total = 54.4 + 24.72

= 79.12eV

Hope it will help you...

#phoenix⭐

neet71: thanks
Answered by IlaMends
4

Answer:The total energy required to ionize the helium atom completely is 79.12 eV

Explanation:

He\rightarrow He^++1e^-,Delta H=E_1

Energy required to remove an electron from helium atom = E_1

He^+\rightarrow He^{2+}+1e^-,Delta H=E_2

Energy require to remove an electron from singly ionized helium atom =E_2

Since in hydrogen atom and singly ionized helium ion has single electron , the energy required to remove an electron is 13.6 eV

For hydrogen =E=13.6 Z^2, Z=1 we get 13.6 eV.

For helium ion = E_2=13.6\times (2)^2=54.4 eV

E_2=54.4 eV

E_2=2.2\times E_1

E_1=\frac{54.4 eV}{2.2}=24.72 eV

The total energy required to ionize the helium atom completely is :

E_1+E_2=24.72 eV+54.4eV=79.12 eV

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