Question

The energy stored in a capacitor of capacitance 100uF 50 J. Its potential difference is
o
50 V
500 V
1000 V
1500 V​

Answer 1

Explanation:

E= 0.5 CV^2

50= 0.5× 100 × V^2 ×10^-6

V= 1000V

Answer 2

Given,

Energy stored=50J

Capacitance=100uF

To Find,

Potential difference of capacitor.

Solution,

To find energy stored in the capacitor ,

E= 1/2 CV²

50= 0.5× 100 × V² ×10^-6

V= 1000V

Hence, its potential difference is 1000V(Option C).