Question

The energy stored in a soap bubble of diameter 6cm and T=0.04N/m is nearly​

Answer 1

Explanation:

Energy stored = 2×S×A

Energy stored=2×.04×4×3.14×( 6/2*100)^2

Energy Stored=0.9×10^-3

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Answer 2

Given:

A soap bubble of diameter 6cm and T=0.04N/m.

To Find:

The energy is stored in a soap bubble of diameter 6cm and T=0.04N/m.

Solution:

To find the energy stored in a soap bubble of diameter 6cm and T=0.04N/m we will follow the following steps:

As we know,

Energy stored per unit surface area = 2 times of surface tension.

Surface tension is taken two times because a soap bubble has two surfaces.

So,

Energy = 2× surface tension× surface area.

E = 2×S×A

Here, E = energy, S = surface tension and A = surface area in metre squares.

radius = half of diameter = 3cm or 0.03m.

A = 4πr²

Now,

Putting values in the above formula we get,

E = 2 ×0.4×4×π × (0.03)² = 0.009 joule.

Henceforth, the energy stored in a soap bubble of diameter 6cm and T=0.04N/m is nearly 0.009 joule.