Question

The energy used by the iron for 2 min is 44kJ at a voltage of 240 volt . How large the current is in the iron ?​

Answer 1

Explanation:

energy = VIt

44 x 1000= 240 x I x 2 x 60..

I = (44x1000)/240 x 120

I=440/24x12

I=110/72

I=55/36A