Question

The engine of a car applies a force of 4200N . if the mass of car is 2 metric tonne and coefficient of friction is 0.1. the velocity acquired by car after 10sec is

Answer 1

Friction force = 0.1 *N = 0.1*2000=-200N 
Net force = force applied +frictional force=4200-200=4000N 
Now using F=ma 
4000=2000*a 
A=2m/s^2 


Now using v=u+at 
V=2*10 
V=20m/s