Question

The engine of an electric train 72m long passes a stationery car with a velocity of 6 metre per second when the tail in of the train and passes the same ka its velocity is 9 metre per second calculate the acceleration of the car and time taken by light to pass the car

Answer 1

Answer:

0.3125 m/sec2

Explanation:

using the third equation of motion

v2-u2 = 2aS

S is the distance travel= length of train = 72 m

Given, v= 9 m/sec and u= 6 m/sec

(9)2 -(6)2= 2×a×72

So, acceleration a, =0.3125 m/sec2

Now, using first equation of motion,we get time t

v=u+a×t

9=6+0.3125×t

and t= 9.61 sec