Question

the engine of train moving with uniform acceleration passes an electric Pole with velocity u and the last compartment with velocity v ,the length of train that has passed the pole when the veolity is v+u/2 if the total length of train is l​

Answer 1

Answer:

c

Explanation:

2u2+v2

(1) length of train :- l

When last compartment passes through pole distance covered by first compartment is l

∴v2=u2+2al

∴a=2lv2−u2

Now, when middle post passes, distance covered by first compartment is 2l

∴vf2=u2+2Ral

=u2+(2lv2−u2)l=2v2+u2

∴vf=2v2+u2