the entanlpy of formation of
methane Co2 and H20 are- 17.9 kcal,
-94kcal and- 68.4 Kcal calculate the
enthalpy
combustion of methane at ordinary temperature
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1
Answer:
Explanation:
The required equation for the combustion of methane is:
CH
4
+2O
2
⟶CO
2
+2H
2
O;ΔH=?
ΔH
=ΔH
f(products)
−ΔH
f(reactants)
=[ΔH
(CO
2
)
+2×ΔH
(H
2
O)
]−[ΔH
(CH
4
)
+2×ΔH
(O
2
)
]
=[(−398.8)−2×241.6]−[(−76.2)−2×0]=−805.8 kJmol
−1
Heat evolved by burning 22.4 litre (1 mole) methane=−805.8 kJ.
So, heat evolved by burning 1000 litre (1 m
3
) methane=
22.4
805.8
×1000=−35973.2 kJ
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