The enthalpy of combustion of ethane, graphite and
dihydrogen at 298 K respectively are -1560 kJ mol-1, -
393.5 kJ mol-1 and - 285.8 kJ mol-1. The enthalpy of
formation of C2H6 is
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1
Answer:
ANSWER
CH
4
+2O
2
⟶CO
2
+2H
2
O;ΔH
1
=−890kJmol
−1
...(i)
C+O
2
⟶CO
2
;ΔH
2
=−393.5kJmol
−1
...(ii)
2H
2
+O
2
⟶2H
2
O;ΔH
3
=2×(−285.8)kJmol
−1
...(iii)
Required reaction →C+2H
2
⟶CH
4(g)
;ΔH
f
=?
From equation(ii)-(i)+(iii)
ΔH
f
=(−393.5)+890.3+2(−285.8)=−74kJmol
−1
Hence option A is correct.
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