The enthalpy of formation of CO2, H20 and ethane gas are -393.5k),
-286kjand -84k) respectively. Enthalpy of combustion of ethane gas is
a. -1561kJ
b. +1561k)
c. -890k) d. None of these
Answers
Answered by
0
Answer:
The required chemical equation for combustion of ethane is
2C
2
H
6
(g)+7O
2
(g)=4CO
2
(g)+6H
2
O(l);ΔH
o
=?
The equation involves 2 moles of C
2
H
6
; heat of combustion of ethane will be
2
ΔH
o
ΔH
o
=ΔH
f(products)
o
−ΔH
f(reactants)
[4×ΔH
(CO
2
)
o
+6ΔH
(H
2
O)
o
]−[2ΔH
(C
2
H
6
)
o
+7ΔH
(O
2
)
o
]
=[4×(−94.1)+6×(−68.3)]−[2×(−21.1)+7×0]
=−744.0kcal
=
2
ΔH
o
= Heat of combustion of ethane
=−
2
744.0
=−372.0 kcal
Explanation:
please follow me and vote me and like me
Answered by
1
The enthalpy of formation of CO2, H20 and ethane gas are -393.5k),
-286kjand -84k) respectively. Enthalpy of combustion of ethane gas is none of these
Similar questions