Chemistry, asked by anilsaroha074, 1 month ago

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The enthalpy of formation of NH3(g) as per the following reaction is -46.11 kJ/mol
at 298 K.
N2(g) + 3H2(g) = 2 NH3(g)
Calculate the value of enthalpy of formation of NH3(g) at 100 °C. The c; (JK"mol")
values are given as: N2(g) = 29.12; H2(g) = 28.82; NH3(g) = 35.06. Assume the
given heat capacity values to be temperature independent in the range.​

Answers

Answered by geetarani9438
0

Answer:

as" (and any subsequent words) was ignored because we limit queries to 32 words.

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