Question

The equal sides of an isosceles triangle are 8 cm long and the radius of its circumcircle is 5cm . calculate the length of its third side ​

Answer 1

Answer:

Third Side = 2 × √23.04

Step-by-step explanation:

Let OD=x

Consider tri. OBD,

BD²=OB²-OD²

5²-x²

BD = √5²- x²

√25-x

Consider tri. ABD,

BD²=AB²-AD²

= 8²-(5+x)²

=64-25-10x-x²

25-x² = 39-10x-x²

25-39 = -10x-x²-x²

-10x = -14

x = 14/10

= 1.4

BD² = BO²-OD²

= 5²-1.4²

= 25-1.96

=23.04

BD = √23.04

Therefore, BC = 2√23.04

Third Side = 2 × √23.04

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