Math, asked by busyserver404, 1 year ago

The equation 
{(24x^2+25x−47)÷(ax−2)} = (−8x−3) − {53 ÷(ax−2)} is true for all values of x≠(2÷a), where a is a constant.

What is the value of a?

A) -16
B) -3
C) 3
D) 16

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Answers

Answered by TheLostMonk
3
◆hiii◆ here is your solution ◆◆
◆hope it helps ◆
◆thankyou◆
Attachments:

busyserver404: In second page 1st line. You take '-' common form ax-2. It should b -(-ax+2) but you had written it as -(ax+2)
TheLostMonk: there is no last line check it another page , i take minus common , ,at the end 8x -3 like line is not included in first page
busyserver404: Got your mistake?
TheLostMonk: where
busyserver404: Check second page. You take minus common wrongly. It should be - ( -ax + 2 )
TheLostMonk: yes //
TheLostMonk: thanks for reminding ,
TheLostMonk: i modified it
busyserver404: :D welcm
TheLostMonk: ^_^ sry
Answered by LittleNaughtyBOY
2

✔️✔️❤️❤️✔️✔️

The equation 

{(24x^2+25x−47)÷(ax−2)} = (−8x−3) − {53 ÷(ax−2)} is true for all values of x≠(2÷a), where a is a constant.

What is the value of a?

SOLUTION : The value of a = -3

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