The equation
{(24x^2+25x−47)÷(ax−2)} = (−8x−3) − {53 ÷(ax−2)} is true for all values of x≠(2÷a), where a is a constant.
What is the value of a?
A) -16
B) -3
C) 3
D) 16
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busyserver404:
In second page 1st line. You take '-' common form ax-2. It should b -(-ax+2) but you had written it as -(ax+2)
there is no last line check it another page , i take minus common , ,at the end 8x -3 like line is not included in first page
Got your mistake?
where
Check second page. You take minus common wrongly. It should be - ( -ax + 2 )
yes //
thanks for reminding ,
i modified it
:D welcm
^_^ sry
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The equation
{(24x^2+25x−47)÷(ax−2)} = (−8x−3) − {53 ÷(ax−2)} is true for all values of x≠(2÷a), where a is a constant.
What is the value of a?
SOLUTION : The value of a = -3
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