Math, asked by busyserver404, 1 year ago

The equation
{(24x^2+25x−47)÷(ax−2)} = (−8x−3) − {53 ÷(ax−2)} is true for all values of x≠(2÷a), where a is a constant.

What is the value of a?

A) -16
B) -3
C) 3
D) 16

First one with correct solution will be awarded with Brainliest.

Answers

Answered by TheLostMonk

◆hiii◆ here is your solution ◆◆
◆hope it helps ◆
◆thankyou◆

Attachments:

busyserver404: In second page 1st line. You take '-' common form ax-2. It should b -(-ax+2) but you had written it as -(ax+2)

TheLostMonk: there is no last line check it another page , i take minus common , ,at the end 8x -3 like line is not included in first page

busyserver404: Got your mistake?

TheLostMonk: where

busyserver404: Check second page. You take minus common wrongly. It should be - ( -ax + 2 )

TheLostMonk: yes //

TheLostMonk: thanks for reminding ,

TheLostMonk: i modified it

busyserver404: :D welcm

TheLostMonk: ^_^ sry

Answered by LittleNaughtyBOY

✔️✔️❤️❤️✔️✔️

The equation

{(24x^2+25x−47)÷(ax−2)} = (−8x−3) − {53 ÷(ax−2)} is true for all values of x≠(2÷a), where a is a constant.

What is the value of a?

SOLUTION : The value of a = -3

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