The equation 24x2+25x−47ax−2=−8x−3−53ax−2 is true for all values of x≠2a, where a is a constant.
What is the value of a?
A) -16
B) -3
C) 3
D) 16
Answers
Answered by
4
✌️✌️Hey mate,
Multiply both sides of the given equation by ax−2.
When you multiply each side by ax−2, you should have:
24x2+25x−47=(−8x−3)(ax−2)−53
You should then multiply (−8x−3) and (ax−2) using FOIL.
24x2+25x−47=−8ax2−3ax+16x+6−53
Then, reduce on the right side of the equation
24x2+25x−47=−8ax2−3ax+16x−47
Since the coefficients of the x2-term have to be equal on both sides of the equation, −8a=24, or a=−3.
so answer is -3.
thanks...
nice to help you ✌️✌️
Multiply both sides of the given equation by ax−2.
When you multiply each side by ax−2, you should have:
24x2+25x−47=(−8x−3)(ax−2)−53
You should then multiply (−8x−3) and (ax−2) using FOIL.
24x2+25x−47=−8ax2−3ax+16x+6−53
Then, reduce on the right side of the equation
24x2+25x−47=−8ax2−3ax+16x−47
Since the coefficients of the x2-term have to be equal on both sides of the equation, −8a=24, or a=−3.
so answer is -3.
thanks...
nice to help you ✌️✌️
ahmernaveed:
thanks
Answered by
3
Hey there
Here ur answer
ur ans is option C and that is 3.
Here, u wanna to multiply both sides to the gn equation by ax−2.
thn,
→24x2+25x−47=(−8x−3)(ax−2)−53
Using Foil, multiply (−8x−3) and (ax−2)
→24x2+25x−47=−8ax2−3ax+16x+6−53
Thn, decrease the RHS of the equation
→24x2+25x−47=−8ax2−3ax+16x−47
so,
→ −8a = 24.
→ a = 24/8
→ a = 12/4
→ a = 3
So, ∴ The value of a is 3.
Hope this helps u
be brainly
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