Question

The equation 2x2 + kx +3=0 has two equal roots, then the value of ‘k’ is ____.
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Answer 1

Answer:

$\huge{\underline{\underline{\sf{꧁AnSwEr꧂}}}}$

GIVEN that

Eq 2x²+kx+3=0 has equal roots

We know the condition for equal roots

D=0

$D = b {}^{2} - 4ac$

then

$b { }^{2} - 4ac = 0$

Here :

a=2,b=k,C=3

Put the values we get

$(k) {}^{2} - 4 \times 2 \times 3 = 0 \\ (k) {}^{2} - 24 = 0 \\ (k) {}^{2} = 24 \\ k = \sqrt{24} \\ k = 2 \sqrt{6}$

꧁Hence the value of K=2√6꧂