The equation 4x^2=4x has following solution/solutions *
a)0,-1,. b)0,1. c)1,-1. d)0,4 which is correct pls help
Answers
Answered by
1
Answer:
Value of x is 0
Hope this helps you
Answered by
1
Answer:
4x^2 - 4x=0
4x(x - 1) =0
so 4x=0
x=0
Or x-1=0
=> x=1
so solution is 0, 1 (b)
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