Question

The equation Bv At dt dv − = is describing the rate of change of velocity of a body
falling from rest in a resisting medium. Find the dimensions of ‘A’ and ‘B’.

Answer 1

Given, dv/dt = At - Bv

Here , dv/dt is rate of change of velocity , v is velocity and t is time.

So, dimension of A = dimension of {dv/dt}/dimension of the

= [LT⁻²]/[T] = [LT⁻³]

∴ dimension of A = [LT⁻³]

Dimension of B = dimension of {dv/dt}/dimension of v

= [LT⁻²]/[LT⁻¹] = [T⁻¹]

∴ dimension of B = [T⁻¹]

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Answer 2

Explanation:

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