THE EQUATION FOR BURNING OF OCTANE IS:
2C8H18+5O2----------->16CO2+ 18H2O
1. HOW MANY MOLES OF CARBON DIOXIDE ARE PRODUCED WHEN 1 MOLE OF OCTANE BURNS
2. WHAT VOLUME AT STP OCCUPIED BY THE NUMBER OF MOLES IN QUESTION 1 ABOVE
3. IF RELATIVE MOLECULAR MASS OF CARBON DIOXIDE IS 44 WHAT IS THE MASS OF CARBON DIOXIDE PRODUCED BY BURNING TWO MOLES OF OCTANE
Answers
Explanation:
So, doing the math (8 x 12 + 1 x 18), we see that octane weighs 114 grams/mole. If you combusted all of the octane to carbon dioxide, each of the eight carbon atoms would become part of a CO2 molecule. Thus, you would have eight CO2 molecules per octane molecule burned--or eight moles of CO2 per mole of octane burned.
The most common example is the molar volume of a gas at STP (Standard Temperature and Pressure), which is equal to 22.4 L for 1 mole of any ideal gas at a temperature equal to 273.15 K and a pressure equal to 1.00 atm.
The equation for the burning of octane is : 2C8H18 + 25O2 → 16CO2 + 18H2ORead more on Sarthaks.com - https://www.sarthaks.com/285025/relative-molecular-mass-carbon-dioxide-what-carbon-dioxide-produced-burning-moles-octane
hope it helps..!!
Answer:
8 moles
one mole of octane forms 8 moles of CO2 on burning.