Question

the equation of a circle passing through (3, - 6 )and touching both the Axes is ​

Answer 1

Answer:

general equation of circle is

( x- h)2+(y- k)2=R2.

when circle touches both the axis then h=k=R.

( x-h)2+(y-h)2=h2.

Now this circle passes through (3,-6) so (3-h)²+(-6-h)2= h2.

h2+6h+45=0.

discriminant=-be,hence h is imaginary.

so there will be no circle under this condition.

HOPE THIS HELP. plz