Question

the equation of a line is 2x-2√3y - √3=0 . find y intercept .​

Answer 1

Answer:

Step 1: Convert the given equation of the line in the slope-intercept form y = mx + c.

∴2x-2√3y - √3=0

$∴ \frac{1}{ \sqrt{3} } x - y - 2 = 0 \\ ∴ y = \frac{1}{ \sqrt{3} } x - 2$

Step II: Then, the co-efficient of x is slope (m) and the constant term term with its proper sign is y-intercept (c).

∴the y intercept = c = -2

Answer 2

Concept:

The intercept theorem states if a transversal makes equal intercepts on three or more parallel lines, then any other line cutting them will also make equal intercepts.

The Y Intercept Formula of a line Ax - By+ C=0 is

                                                  y= mx+c

Where,

m = slope of the line.

c = y-intercept of the line.

Given:

Equation of line 2x-2√3y - √3=0

Find:

We are asked to find the value of "y" intercept.

Solution:

By considering the given equation 2x-2√3y - √3=0

 2√3y = 2x - √3

        y = 2/2√3x - √3/2√3

        y= 1/√3x - 1/2

Value of "c" = -1/2

Hence y-intercept of the line is -1/2

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