The equation of a line is 3x+4y - 7=0. find
i. The slope of the line.
ii. The equation of a line perpendicular to the given line
and passing through the intersection of the lines X-y=-2
and 3x+y-10=0.
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Answer:
3x + 4y – 7 = 0 .....(1)
1) Slope of the line m =
coefficient of x
coefficient of y
=
−
3
4
coefficient of xcoefficient of y=-34
2) Equation of line perpendicular to the given line
4x – 3y = λ ......(2)
Solving the equations x – y + 2 = 0 and 3x + y – 10 = 0, point of intersection is (2, 4).
Line (2) passes through points (2, 4).
4(2) – 3(4) = λ ⇒ λ = –4
Hence, the equation of required line is
4x - 3y + 4 = 0
Step-by-step explanation:
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