Question

The equation of a line passing through origin and parallel to the line 2x + 3y = 6 is ?

Answer 1

Answer:

2x+3y=0

Explanation:

Since the required line is parallel to 2x+3y=6

Therefore, its slope is -2/3 i.e same as the given line.

So required line is of 2x+3y+c=0 type.

Since it passes through 0,0

0,0 satisfies it. Therefore,C=0

Answer 2

Answer:

2x + 3y = 0

Explanation:

2x + 3y = 6

Slope (m1) = - Coefficient of x

                      Coefficient of y

m1 = - 2

         3

∵ Lines are parallel

∴ m1 = m2

y - 0 = - 2

x - 0      3

y = - 2

x      3

∴ 2x + 3y = 0

Hope it helps you....