Math, asked by kondetisyamala17, 9 months ago

the equation of a line perpendicular to x+3y=7​

Answers

Answered by avinashxkumarz123
3

Answer:

equation = x + 3y = 7

perpendicular line passing through (0,1)

Step-by-step explanation:

x+3y=7; written in the slope intercept form will be

y= -(1/3)x + (7/3) where the slope will be -1/3 then the slope of the perpendicular line to this line will be 3.

writing the new equation in the point slope form we have

(y-1) = 3(x-0)

the equation will be:

y = 3x + 1

Answered by haijessie
0

equation = x + 3y = 7

perpendicular line passing through (0,1)

Step-by-step explanation:

x+3y=7; written in the slope intercept form will be

y= -(1/3)x + (7/3) where the slope will be -1/3 then the slope of the perpendicular line to this line will be 3.

writing the new equation in the point slope form we have

(y-1) = 3(x-0)

the equation will be:

y = 3x + 1

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