Question

the equation of a particle performing shm is given by x=8sin(5\pit+\pi/3)cm. Determine the displacement & phase angle of particle at t=2 second​

Answer 1

Answer:

x=5sinπt+12sin(πt+π/2)

=5sinπt+12cosπt

=13sin(πt+θ) where cosθ=5/12

Amplitude, A=max(x)=13 cm

Time period, T=2π/ω=2π/π=2 s

Initial phase, α=∠(x)

t=0

=θ

α=cos

−1

(5/12)

Explanation:

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