Physics, asked by sreekumarir2858, 1 year ago

The equation of a projectile is y = $\sqrt{3x}-\frac{gx^{2}}{2}$ The angle of projection is given by
(a) tan θ = $\frac{1}{\sqrt{3}}$
(b) tan θ= $\sqrt{3}$
(c) $\frac{\pi}{2}$
(d) zero.

Answers

Answered by Anonymous

may be the correct answer is a

Anonymous: hi shashank

Anonymous: Hii

Previous Question

Next Question

Similar questions

Social Sciences, 6 months ago

English, 6 months ago

English, 6 months ago

Geography, 1 year ago

Physics, 1 year ago

At what angle must the two forces (x + y) and (x – y) act so that the resultant may be $\sqrt{(x^{2} + y^{2})}$ ? (a) $\cos^{-1}[-(x^{2} + y^{2})}/{2(x^{2} - y^{2})}]$ (b) $\cos^{-1}[-2{(x^{2} - y^{2})}/{(x^{2} + y^{2})}]$ (c) $\cos^{-1}[-{(x^{2} + y^{2})}/{(x^{2} - y^{2})}]$ (d) $\cos^{-1}[-{(x^{2} - y^{2})}/{(x^{2} + y^{2})}]$ ...

Chemistry, 1 year ago

Biology, 1 year ago

Math, 1 year ago