The equation of a transverse wave traveling in a rope is given by txy ),( =10 sin[π 01.0( x − 00.2 t ],) where y and x are expressed in centimeters and t in seconds. (a) Find the amplitude, frequency, velocity, and wavelength of the wave. (b) Find the maximum transverse speed of a particle in the rope.
Answers
Answered by
2
Answer:
The given equation is y=10sinπ(0.01πx−2πt)
Hence ω= coefficient of t=2π
⇒ maximum speed of the particle vmax=aω=10×2π
=10×2×3.14=62.8=63m/sec
Explanation:
Similar questions