Question

The equation of burning of ethane is given below:
2C2H6 + 7O2 ----> 4CO2 + 6H2O
(i) How many moles of Carbon dioxide are produced when one mole of Ethane burns
(ii) What volume, at STP, is occupied by the number of moles determined in (i)
(iii) What is the volume of oxygen consumed when 60g of Ethane burns.
(Pls tell the answer as quick as possible)​

Answer 1

Answer:

1) By applying stoichiometry

n (CO2)/4 = n (C2H6)/2

n (CO2) = 4/2 = 2 moles

2) By n = V/22.4

V = 2×22.4

V = 44.8 lit.

3) 60g ethane = 2 moles of ethane

By stoichiometry

2/4 = n (O2)/7

n (O2) = 3.5

3.5×22.4 = V (O2)

V (O2) = 78.4 lit.

Hope it helps..

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Answer 2

Answer:

I hope you understand

Explanation:

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