tell me the answer please
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To find: Cos^2 67 - Sin^2 23
Formula: Cos^2A - Sin^2B = Cos ( A + B ) * Cos ( A - B )
Here, A = 67, B = 23
Substituting them, We get: Cos (67 + 23 ) * Cos( 67 - 23 )
Cos ( 90 ) * cos ( 45 )
Substituting values, 0 * 1/√2 .
Hence, Cos^2 67 - Sin^2 23 = 0
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Answer:
change sign into cos check NCERT book
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