Question

the equation of line is 3x-4 +12=0 it interests x axis in point a and y axis in point b find the coordinates of point a and b find the length of ab

Answer 1

3x-4y+12=0
then x intercept is -12/3 = -4
y intercept is 12/4 = 3
:.coordinates of a (-4,0) & b (0,3)
ab =
$ab = \sqrt{ ( - 4) {}^{2} + 3 {}^{2} }$
:.ab = 5