Question

the equation of line or is 3y-3x+7=0 .write down the slope of the line pq and calculate the angle that the line of makes with the positive direction of X-axis ​

Answer 1

Given :  the equation of line is 3y-3x+7=0

To find :  slope of the line , the angle that the line of makes with the positive direction of X-axis ​

Solution:

3y-3x+7=0

=> 3y = 3x  - 7

=> y = x  - 7/3

Comparing with

y = mx  + c

m = 1

Slope of  line  is  1

or

3y  - 3x + 7 = 0

3dy/dx -  3 = 0

=> dy/dx = 1

Slope of line = 1

Slope of line = Tan ( angle that the line of makes with the positive direction of X-axis ​)

=> Tan ( angle that the line of makes with the positive direction of X-axis ​) = 1

=> angle that the line of makes with the positive direction of X-axis  = 45°  or  π/4  

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