Question

The equation of line passes (–1, 4) and perpendicular to the line 3x + 4y + 5 = 0 is ​

Answer 1

Slope of the given line 3x + 4y + 5 = 0 is Slope of the line perpendicular to the given line is -1 -1 4 = m₁ (-³) 3

3 4 m₁ = -

The equation of the line which is perpendicular to 3x + 4y + 5 = 0 and passing through point (4,-5) is y - y₁ = m(x − x₁)

⇒ y − (-5) = (x − 4)

⇒ 3y + 15 = 4x - 16

⇒ 4x - 3y - 31 = 0